1.

The threshold wavelength for the ejection of electron for metal X is 330 nm. The work function for photoelectric emission from metal X is (h=6.6xx10^(-34)Js)

Answer»

`1.2xx10^(-18)J`
`1.2xx10^(20)J`
`6xx10^(-19)J`
`6xx10^(-12)J`

Solution :Work function
`hv_(0)=(hc)/(lamda_(0))=(6.6xx10^(-34) xx3.0xx10^(8))/(330xx10^(-9))` `=6.0xx10^(-19)J`


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