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The threshold wavelength of Na element is 6800 Å.Its work function is ……….xx10^(-19)J.(h=6.625xx10^(-34)Js,C=3xx10^(8)ms^(-1))

Answer»

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Solution :`phi=hf_(0)=(hc)/(lambda_(0))`
`THEREFORE phi=(hc)/(lambda_(0))=(6.625xx10^(-34)xx3xx10^(8))/(68xx10^(-8))`
`=0.2922xx10^(-18)=2.922xx10^(-19)J`


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