The time of revolution of an electron around a nucleus of charge `Ze` in `n`th Bohr orbit is directly proportional toA. `n`B. `(n^(3))/(Z^(2))`C. `(n^(2))/(Z)`D. `(Z)/(n)`

The time of revolution of an electron around a nucleus of charge `Ze`

1.	The time of revolution of an electron around a nucleus of charge `Ze` in `n`th Bohr orbit is directly proportional toA. `n`B. `(n^(3))/(Z^(2))`C. `(n^(2))/(Z)`D. `(Z)/(n)`
Answer» Correct Answer - B `T = (2pi r)/(v) , r =` radius of `nth` orbit `= (n^(2)h^(2))/(pi mZe^(2))` `v =` speed of `bar(e)` in nth orbit `= (ze^(2))/(2 epsilon_(0)nh)` `:. T = (4epsilon_(0)^(2)n^(3)h^(3))/(mZ^(2)e^(4)) rArr T prop (n^(2))/(Z^(2))`

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The time of revolution of an electron around a nucleus of charge `Ze` in `n`th Bohr orbit is directly proportional toA. `n`B. `(n^(3))/(Z^(2))`C. `(n^(2))/(Z)`D. `(Z)/(n)`

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