1.

The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become

Answer»

10 hours
80 hours
40 hours
20 hours

SOLUTION :According to Kepler.s LAW of PLANETARY motion, `T^(2) prop R^(3)`
`therefore T_(2) = T_(1) ((R_(2))/(R_(1)))^(3//2) = 5 xx [ (4R)/(R) ]^(3//2) = 40` hours


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