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The time period of a simple pendulum of length 9.8 m isA. 0.159 sB. 3.14 sC. 6.5 sD. 6.28 s |
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Answer» Correct Answer - D (d) Time period `T=2pisqrt((k)/(m))` Given , `g=9.8 ms^(-2), l=9.8 m` `T=2pisqrt((9.8)/(9.8))=2pi=2xx3.14=6.28 s` |
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