InterviewSolution
Saved Bookmarks
| 1. |
The time period of a simple pendulum of length L as measured in an elevator descending with acceleration g / 3 isA. `2 pi sqrt((3L)/g)`B. `pi sqrt((3L)/(g)`C. `2 pi sqrt(((3L)/(2g)))`D. `2 pi sqrt((2L)/(3g)` |
|
Answer» Correct Answer - C |
|