The time period of a thin bar magnet in Earth's magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be

The time period of a thin bar magnet in Earth's magnetic field is T. I

1.	The time period of a thin bar magnet in Earth's magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be
Answer» `T//2` T `sqrt2T` 2T Solution :`T =2pisqrt(I/(MB_(H)))=2pi SQRT((Ml^(2))/(12 XX lm xx B_(H)))` For HALF portion, `T. =2pi sqrt(M/2).(l^(2)xx2)/(4xx12xxlxxmxxB_(H))` `therefore T./T =sqrt(4/1)=2/1 IMPLIES T.=2T`

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The time period of a thin bar magnet in Earth's magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be

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