1.

The time period of oscillations of a freely suspended magnetic needle is given by

Answer»

`T= 2PI SQRT((I)/(mB_H))`
`T= 2pi sqrt((mB_H)/(I))`
`T= sqrt((I)/(mB_H))`
`T= 2pi sqrt((B_H)/(MI))`

SOLUTION :`T= 2pi sqrt((I)/(mB_H))`


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