1.

The time period of planet X around sun is 8 times that of Y. The distance of X from the sun is how many times greater than that of Y ?

Answer»

4 times
3 times
`6(1)/(2)` times
`5(1)/(2)` times

Solution :`(T_(1)^(2))/(T_(2)^(2)) = ((R_(1))/(R_(2)))^(3) rArr (R_(1))/(R_(2)) = ((T_(1))/(T_(2)))^(2//3)`
`(R_(1))/(R_(2))=(8)^(2//3) rArr R_(1)=4R_(2)`.
Thus CORRECT choice is (a).


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