1.

The time required for the light to pass through a glass slab (refractive index = 1.5) of thickness 4 mm is (c = 3 xx 10^(8)ms^(-1)"speed of light in free space")

Answer»

`10^(-11)`
`2 xx 10^(-11) s`
`2 xx 10^(11)s`
`2 xx 10^(-5)s`.

SOLUTION :(b) We know, `n_(a) c_(a) = n_(g) c_(g)`
`(n_(g))/(n_(a)) = (c_(a))/(c_(g))`
`(3)/(2) = (3xx10^(8))/(c_(g))`
`c_(g) = 2 xx 10^(8)`
We have, Time = `("DISTANCE")/("Speed")`
`t = (4 xx 10^(-3))/(2 xx 10^(8))`
or "" `t = 2 xx 10^(-11) s.`


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