1.

The time taken by A.C. voltage of frequency 50 Hz to change from zero to maximum is ……. ms.

Answer»

5
10
20
50

Solution :`V=V_m SIN omegat`
If `V=V_m` then 1 = sin `omegat`
`therefore omegat=pi/2`
`therefore t=(pixxT)/(2xx2pi) [because OMEGA=(2pi)/T]`
`therefore t=T/4`
`therefore t=1/(50xx4) [ because T=1/f = 1/50]`
`therefore t=1/200`
`therefore t=5xx10^(-3)` s
`therefore` t=5 MS


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