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- the time, takento Comple te3/41he co aud the. timeComplete halt oakenhe,イe action |
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Answer» amount left when 3/4th of the reaction will be completed = 1/4th so T¾ = 1/k*(ln[A/(A/4)])=> T¾= ln4/k and similarly T½ = 1/k*(ln[A/A/2]) = ln2/k ao, ratio T¾/T½ = ln4/ln2 = 2 please solve on paper thanks |
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