1.

The top of the tower of the Olympic Stadium is 72 metres from the see level. Howfar in the sea is the horizon assuming the globe to be a sphere whose radius is6378 km? How far is the horizon assuming the errors in the measures: 72 mt 2 mand 6378 km + 0.2 %?​

Answer»

ANSWER:(R + h)2= R2 + OG2

or

OG2 = (R + h)2 − R2 .

But if we expand the TERM (R + h)2 = R2 + 2 R h + h2, the R2 terms cancel, and we find

OG = SQRT ( 2 R h + h2 ) .

It's customary to use the fact that h << R at this point, so that we can neglect the second term. Then

OG ≈ sqrt ( 2 R h )

is the distance to the horizon, neglecting refraction.

Step-by-step explanation:


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