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The torque of force F about originis(3) τ5(V3-1)/ Nm(4)-:3jN |
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Answer» Origin vector is ( 1i+1j) and F = 5√3i + 5j so, T = F×r = (5√3i+5j)×(i+j) = (5√3 - 5)k = 5(√3-1)k N-m option 3 |
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