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The torsion modulus of a spiral spring is 2 N·m/rad. The spring is turned 10 times. What is the work done?

Answer»


SOLUTION :The WORK done in TWISTING the SPRING by an angle a is equivalent to the work done in extending it by a length I, which is expressed by the formula `W= 1//2Fx= 1//2kx^2` .Therefore the work sought is
`W=1/2Malpha=1/2//alpha^2`
Note that the torsion modulus `f = M//alpha`is an analogue of the spring constant `k = F//x`


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