1.

The total binding energy of an alpha-particle (._(2)He^(4)) is 24.4 MeV, where as the total binding energy of a deutron (._(1)H^(2)) is merely 2.2 MeV. When two deutrons are made to combine

Answer»

An `ALPHA`-PARTICLE will be obtained
An amount of 22.2 MEV ENERGY will be RELEASED
An amount of 20.0 MeV energy will be released
An amount of 2.22 MeV energy will be released

Solution :`[2.4-(2.2)(2)]=20.0MeV`


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