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The total energy of a particle in SHM is E. Its kinetic energy at half the amplitude from mean position will beA. E/2B. E/3C. E/4D. 3E/4 |
Answer» Correct Answer - D KE`=(1)/(2)momega^(2)(A^(2)-x^(2))implies(1)/(2)momega(A^(2)-(A^(2))/(4))" "(becausex=(A)/(2))` `=(3)/(4)xx(1)/(2)momega^(2)A^(2)=(3)/(4)E` |
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