1.

The total energy of a particle in SHM is E. Its kinetic energy at half the amplitude from mean position will beA. E/2B. E/3C. E/4D. 3E/4

Answer» Correct Answer - D
KE`=(1)/(2)momega^(2)(A^(2)-x^(2))implies(1)/(2)momega(A^(2)-(A^(2))/(4))" "(becausex=(A)/(2))`
`=(3)/(4)xx(1)/(2)momega^(2)A^(2)=(3)/(4)E`


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