1.

The total energy of an electron in the first excited state of H atom is - 3.4 eV, then its potential energy in this state is ...eV.

Answer»

`+3.4`
`-3.4`
`-6.8`
`+6.8`

SOLUTION :`(U)/(E)=(U)/(U)=2`
`:.U=2E :. U=2(-3.4)EV:. U=-6.8eV`


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