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The total energy of an electron in the first excited state of the hydrogen atom is about – 3.4 eV. What is (c ) Which of the answers above would change if the choice of the zero of potential energy in changed to (i) + 0.5 eV (ii) – 0.5 eV. |
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Answer» Solution :f the ZERO of P.E. is CHOSEN DIFFERENTLY, K.E. does not change. The P.E. and T.E. of the state, however WOULD alter if a different zero of the P.E. is chosen. When P.E. at `oo` is+ 0.5 eV, P.E. of first EXCITED state will be– 3.4 – 0.5 = – 3.9 eV. When P.E. at `oo` is + 0.5 eV, P.E. of first excited state will be– 3.4 – (– 0.5) = – 2.9 eV. |
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