1.

The total energy of electron in the ground state of hydrogen atom is (-13.6 eV). The kinetic energy of an electron in the first excited state is

Answer»

`6.8` eV
`13.6` eV
`1.7` eV
`3.4` eV

Solution :Total energy in the FIRST excited STATE,
`E_(2) = (E_(1))/(E_(2)) = (E_(1))/(E_(2)) = (-13.6)/(4) = -3.4 eV`
` K.E = - E_(2) = 3.4 eV`


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