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The total energy of electron in the ground state of hydrogen atom is (-13.6 eV). The kinetic energy of an electron in the first excited state is |
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Answer» `6.8` eV `E_(2) = (E_(1))/(E_(2)) = (E_(1))/(E_(2)) = (-13.6)/(4) = -3.4 eV` ` K.E = - E_(2) = 3.4 eV` |
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