The total energy of free surface of a liquid drop is `2pi` times the s – InterviewSolution

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1.	The total energy of free surface of a liquid drop is `2pi` times the surface tension of the liquid. What is the diameter of the drop ? [Assume all terms in SI unit].
Answer» Given, `E=2pi T` `E=T Delta A` `therefore 2pi T=T(4pi r^(2)) " " [because Delta A=4pi r^(2)]` `2r^(2)=1` `r^(2)=(1)/(2)` `therefore r=(1)/(sqrt(2))` Now, Diameter (d) `=2r=2xx(1)/(sqrt(2))` `=sqrt(2)` `=1.414 m.`

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