1.

The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is

Answer»


Solution :3-Bromo-3-cyclopentylhexane has THREE different types of `alpha`-hydrogens marked as (a), (b) and (c) and HENCE can give three structurally isomeriic alkenes. But TWO of these can exhibit geometrical isomerism. Therefore, the total NUMBER of alkenes possible are five as hown below:


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