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The total number of atoms present in0.1 mole of sucrose (C_12H_22O_11)is : |
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Answer» `6.02 XX 10^22` ` = 6.02 xx 10^23 xx 45` 0.1 mole of `C_12H_22O_11` contains atoms ` = 6.02 xx 10^23 xx 45 xx 0.1 = 2.7 xx 10^24` |
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