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The total number of electrons in the human body is typically in the order of 10^(28) . Suppose due to some reason you and your friend lost 1% of this number of electrons. Calculate the electrostatic force between you and your friend separated at a distance of 1m. Compare this with your weight . Assume mass of each person is 60 kg and use point charge approximation. |
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Answer» Solution :Number of electrons in the human body `=10^(28)` Number of electrons in me and my friend after lost of `1%= 10^(28)xx1%` `=10^(28)xx(1)/(100)` `n = 10^(26)` electrons Separation distance d= 1 m Charge of each person q `= 10^(26)xx1.6xx10^(-19)` `q= 1.6xx10^(7)`C ELECTROSTATIC FORCE `F= (1)/(4piepsilon_(0))(q_(1)q_(2))/(r^(2))= (9xx10^(9)xx1.6xx10^(7)xx1.6xx10^(7))/(1^(2))` `F=2.304 xx10^(24)N ` Mass of the person M = 60 kg Accelerationdue to gravity g = `9.8ms^(2)` Weight (W) = mg `=60 xx9.8` W = 588 N Comparison : Electrostatic force is equal to `3.92 xx10^(21)` times of weight of the person. |
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