The total positive charge on a silver nucleus (atomic number :Z=47) is uniformly distributed on a sphere of radius 10^(-10) m . What will be the intensity of electric field at the surface ofthis sphere ?

The total positive charge on a silver nucleus (atomic number :Z=47) is

1.	The total positive charge on a silver nucleus (atomic number :Z=47) is uniformly distributed on a sphere of radius 10^(-10) m . What will be the intensity of electric field at the surface ofthis sphere ?
Answer» SOLUTION :Total CHARGE on sphere , q.=47e = `47xx1.6xx10^(-19)` C Radius of sphere , `r=10^(-10)` m The electric field intensity at the surface of the sphere is given by : `E=1/(4piepsilon_0)q/r^2` `=(9xx10^9xx47xx1.6xx10^(-19))/(10^(-10))^2` `=6.76xx10^12 NC^(-1)`

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The total positive charge on a silver nucleus (atomic number :Z=47) is uniformly distributed on a sphere of radius 10^(-10) m . What will be the intensity of electric field at the surface ofthis sphere ?

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