1.

The total possible number of optically inactive isomers of the complex [Pt(NH_(3))_(2)FClBrI] would be :

Answer»

6
12
3
15

Solution :`[Pt(NH_(3))_(2)FClBrI]" or "Ma_(2)bcde`
Total 9 G.I. out which 3 are TRANS and optically inactive and 6 are optically ACTIVE.


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