1.

The trajectory of a projectile projected from origin is given by the equation y = x - (2x^(2))/(5) .The initial velocity of the projectile is

Answer»

`25 ms^(-1)`
`2 //5 ms^(-1)`
`5 //2ms^(-1)`
`5ms^(-1)`

SOLUTION :`y= ax- bx ^2 , asa=I= TAN thetaimpliestheta= 45^@ `
` b=2/5 =(G)/(2v^2 cos^2 theta)`
` U^2= (5 g)/( 4 cos ^2 theta)`
` U^2= ( 5G )/( 4 cos45^@) = (5g)/(2)= 2.5 g = 25 m//s`


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