1.

The transfer ratio beta of a transistor is 50. The input resistance of the transistor when used in the common emitter mode is 1kOmega . The peak value of the collector alternating current peak voltage of 0.01 V is :

Answer»

`0.25 MUA`
`0.01 muA`
`500 muA`
`100 muA`

SOLUTION :Here , `i_b=V_i/R_i=(0.01)/10^3A=10^(-5)A`
Then , `i_c/i_b=beta=50xx10^(-5)A`
`:. i_c=500 muA`


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