1.

The treatment of CH_(3)MgX " with " CH_(3)C-C-H produces

Answer»

`CH_(3)-CH=CH_(2)`
`CH_(3)C=C-CH_(3)`
`CH_(2)-HC=CH-CH_(3)`
`CH_(4)`

Solution :Writing the REACTION we get
`CH_(3)MgX+CH_(3)-C-=C-H to CH_(3)-C-=CMgX+CH_(4)(g)`


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