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The turbine pits at Niagra Falls are 50m deep. The average horse power develop is 5000. If the efficiency of the generator `85%` , how much water passes through the turbine per minute ? Take `g=10m//s^(2)`. |
Answer» Here, `h=50m, H.P.=5000, eta=85%`, `m_(2)` useful power `=5000HP=5000xx746 wat t`. Total power generated `=(5000xx746)/(85%)=(500xx746xx100)/(85)` `=4.388xx10^(6) wat t` Total work done by the falling water in 1 minute `mgxxh=4.388xx10^(6)xx60J` `m=(4.388xx10^(6)xx60)/(gh)=(4.388xx10^(6)xx60)/(10xx50)` `m=5.39xx10^(5)kg` |
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