1.

The two capacitors, shown in the circuit, are initially uncharged and the cell is ideal.The switch S is closed at t = 0. Which of the following functions represents the current i(t), through the cell as a function of time?Here i_(0), i_(1), i_(2) are constants.

Answer»

`i(t) = i_(0) + i_(1)e^(-t/tau), tau = 3C xx (R)/(3)`
`i(t) = i_(0) + i_(1)e^(-t/tau)+ i_(2)e^(-t/2tau), tau = RC`
`i(t) = i_(1) + i_(1)e^(-t/tau), tau = 3C xx (R)/(3)`
`i(t) = i_(0) + i_(1)e^(-t/tau), tau = 3RC`

Solution :The three branches of the circuits CARRY CURRENTS `i = i_(0), i = i_(1) e^(t/RC)` and `i = i_(2) 2e^(-t/2RC)` respectively. The current through the cell, i() can be foundby using Kirchhoff.s current LAW (or mode law).


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