1.

The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures f_(1) and T_(2) rod in a steady state is given by :

Answer»

`(DQ)/(DT)=(k(T_(1)-T_(2)))/(LA)`
`(dQ)/(dt)=KLA(T_(1)-T_(2))`
`(dQ)/(dt)=(kA(T_(1)-T_(2)))/(L)`
`(dQ)/(dt)=(kL(T_(1)-T_(2)))/(A)`

Solution :As `(dQ)/(dt)=(kA(T_(1)-T_(2)))/(L)`
Correct CHOICE is (c ).


Discussion

No Comment Found

Related InterviewSolutions