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The two ends of a train moving with uniform acceleration pass a certain point with velocity u and v.Find the velocity with which the middle point of the train passes the same point. |
Answer» Solution : Between A,B,`(V^(1))^(2)-u^(2)`=2a s/2 Between B,C ,`v^(2)-(v^(1))^(2)`=2as/2 `IMPLIES(v^(1))^(2)-u^(2)=v^(2)-v^(12)` `2(v^(1))^(2)=v^(2)+v^(2)` Velcity at mid POINT is `v^(1)=sqrt(u^(2)+v^(2))/(2)` |
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