1.

The two plates X and Y of a parallel plate capacitor of capacitance C are given a charge of amount Q each. X IS now joined to the positive cumminal and Y to the negative terminal of a cell of emf E = Q/C: -

Answer»

Charge of amount Q will flow from the negative terminal to the POSITIVE terminal of the cell INSIDE
The total charge on the PLATE X will be 2Q.
The total charge on the plate Y will be zero.
The cell will supply `CE^2`amount of energy.

Answer :A::B::C::D


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