1.

The two plates X and Y of a parallel-plate capacitor of capacitacne C are given a charge of amount Q each. X is now joined to the positive terminal and Y to the negative terminal of a cell of emf varepsilon=Q//C.

Answer»

Charge of amount `Q` will flow fromte positive terminal to the NEGATIVE terminal of the CELL through the capacitor.
The total charge on the plate `X` will be `2Q`
The total charge on the plate `Y` will be zero.
The cell will SUPPLY `Cvarepsilon^(2)` amont of energy.

Answer :A::B::C::D


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