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The two soap of bubbles of equal radii (r and r) coalesce. Then what will be the radius of curvature of the interface between two bubbles? |
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Answer» Solution :For two soap BUBBLE of RADII `r_1` and `r_2` where `r_2 gt r_1`, the radius of CURVATURE of the common interface is GIVEN by `R = (r_1r_2)/(r_2 - r_1)` But, in this case `r_1 = r_2` therefore r_2 - r_1` = 0 R = (`r_1r_2`)/0 = 8 |
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