1.

The uncertainties in the position and velocity of a particle are 10^(-10)m and 5.27 xx 10^(-24) ms^(-1) respectively. Calculate the mass of the particle (h= 6.625 xx 10^(-24) J.s)

Answer»

Solution :We have, `Deltax.(m DELTA v)= (h)/(4pi)`
or `m= (h)/(4pi) XX (1)/(Delta x.Delta v)`
`= (6.625 xx 10^(-34) (kg.m^(2)s^(-1)))/(4 xx 3.14 xx (10^(-10)m) (5.27 xx 10^(-24) MS^(-1)))`
= 0.10kg


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