1.

The uncertainty in the momentum of a particle is 2.5 xx 10^(-16)g cm s^(-1). With what accuracy can its position be determined ? (h= 6.625 xx 10^(-27) erg.s, i.e., g cm^(2)s^(-1))

Answer»

Solution :We have, `Delta x. Deltap= (h)/(4pi)`
or `Delta x= (h)/(4pi) xx (1)/(Delta p)`
`= (6.625 xx 10^(-27)g cm^(2) s^(-1))/(4 xx 3.14 xx (2.5 xx 10^(-16) g cm s^(-1)))`
`=2.11 xx 10^(-12)cm`


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