1.

The uncertainty in the momentum of an electron is 1.0xx10^(-5)kgms^(-1). The uncertainty in position will be (h=6.6xx10^(-34)kgm^(2)s^(-1))

Answer»

`5.25xx10^(-28)m`
`1.05xx10^(-26)m`
`5.25xx10^(-30)m`
`1.05xx10^(-28)m`

Solution :`DELTAX xx Deltap=h/(4pi)`
`DELTA x=h/(4pixx Deltap)=(6.6xx10^(-34))/(4xx2/7xx1xx10^(-5))`
`=5.25xx10^(-30)m`


Discussion

No Comment Found

Related InterviewSolutions