The unit of force in SI system is newton and it is given as 1 newton = 1kg m s^(-2). In CGS system its unit is dyne and it is given as 1 dyne = 1 g cm s^(2). Arrange the following steps in a sequential order to relate the SI unit and CGS unit of force. (a) Write the conversations of kg and m, into g and cm, respectively. (b) Substitute the conversations in 1 newton = 1 kg m s^(2)Write the relation between 1 newton and dyne. (d) Write in place of 1 g cm s^(-2) as 1 dyne

The unit of force in SI system is newton and it is given as 1 newton =

1.	The unit of force in SI system is newton and it is given as 1 newton = 1kg m s^(-2). In CGS system its unit is dyne and it is given as 1 dyne = 1 g cm s^(2). Arrange the following steps in a sequential order to relate the SI unit and CGS unit of force. (a) Write the conversations of kg and m, into g and cm, respectively. (b) Substitute the conversations in 1 newton = 1 kg m s^(2)Write the relation between 1 newton and dyne. (d) Write in place of 1 g cm s^(-2) as 1 dyne
Answer» a c b d a b d c b d a c c d a b Solution :The SI unit of FORCE is newton, 1newton = 1 KG m `s^(2)` . First convert kg and m into G and cm. SUBSTITUTE these conversations in 1 newton = 1 kg m ` s^(-2)` . Now in the place of 1 g cm ``s^(-2)`, write 1 DYNE as 1 newton = `10 ^(5)` dyne.