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The unit sample response of an ideal Hilbert transform is(a) =\(\frac{2}{\pi} \frac{(sin(\frac{πn}{2}))^{2}}{n}\); n≠0(b) =0; n=0(c) True(d) FalseI have been asked this question by my school teacher while I was bunking the class.My doubt is from Design of Hilbert Transformers topic in portion Digital Filters Design of Digital Signal Processing |
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Answer» RIGHT answer is (a) =\(\FRAC{2}{\pi} \frac{(sin(\frac{πn}{2}))^{2}}{n}\); n≠0 The best explanation: We KNOW that the frequency response of an ideal HILBERT transformer is given as H(ω)= -j ;0 < ω < π j ;-π < ω < 0 Thus the unit SAMPLE response of an ideal Hilbert transform is obtained as h(n)=\(\frac{2}{\pi} \frac{(sin(\frac{πn}{2}))^{2}}{n}\); n≠0 h(n)=0; n=0 |
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