The unit vector to the points p1(0,1,0), p2(1,0,1), p3(0,0,1) is(a) (-j – k)/1.414(b) (-i – k)/1.414(c) (-i – j)/1.414(d) (-i – j – k)/1.414The question was posed to me in an online interview.The above asked question is from Position and Distance Vectors topic in chapter Vector Analysis and Applications of Electromagnetic Theory

The unit vector to the points p1(0,1,0), p2(1,0,1), p3(0,0,1) is(a) (-

1.	The unit vector to the points p1(0,1,0), p2(1,0,1), p3(0,0,1) is(a) (-j – k)/1.414(b) (-i – k)/1.414(c) (-i – j)/1.414(d) (-i – j – k)/1.414The question was posed to me in an online interview.The above asked question is from Position and Distance Vectors topic in chapter Vector Analysis and Applications of Electromagnetic Theory
Answer» Right choice is (a) (-j – K)/1.414 To explain: The CROSS product of p1, P2, P3 is a X b = -j – k and its magnitude is 1.414. The unit normal VECTOR is given by, (-j – k)/1.414.

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