1.

The units of surface tension and viscosity of liquids are respectively

Answer»

`kgm^(-1)s^(-1),Nm^(-1)`
`kgs^(-20,kgm^(-1)s^(-1)`
`Nm^(-1),kgm^(-1)s^(-2)`
`kgs^(-1),kgm^(-2)s^(-1)`

Solution :Surface tension
`=("FORCE")/("Length")=N/m=(kgms^(-2))/m=kgs^(-2)`
`F= eta A.(dv)/(DX)`
`eta=F/(A . (dv)/(dx))implieseta= N/(m^(2)XX(ms^(-1))/m)=Nm^(-2)s`
`=kgms^(-2)m^(-2)s=kgm^(-1)s^(-1)`


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