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The upper boundary of class interval 10-19 among the following intervals 0-9 10-19 20-29 30-39 |
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Answer» 10−19,20−29,30−39,...Here the class INTERVALS are not continuous. To MAKE them continuous take the mean of UPPER limit of first class and lower limit of second class.Mean = 219+20 =19.5, which GIVES the upper limit of first class and lower limit of second class for the continuous class intervals. |
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