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The `v-s` and `v^(2)-s` graph are given for two particles. Find the accelerations of the particles at `s=0`. . |
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Answer» `a_(1) = (vdv)/(ds)`, where `v = 20` (at `s = 0`) and `(dv)/(ds) = - (2)/(5)` Then `a_(1) = -8 m//s^(2)` `a_(2) = (1)/(2) (d(v^(2)))/(ds)`, where `(d(v^(2)))/(ds) = - (2)/(5)` then , `a_(2) = - 0.2 m//s^(2)` |
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