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The vale of tan^(-1) tan(5pi/ 6) is ? |
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Answer» TAN(65π)=tan(π−6π) =−tan6π =−31 COS(136π)=cos(2π+6π) =cos(6π)=23 ∴tan−1(3−1)+cos−1(23) =−6π+6π=0. |
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