InterviewSolution
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InterviewSolution
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The value of `(1+Delta)(1-Delta)` is |
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Answer» Correct Answer - C We have, `(1+Delta)(1-grad)f(x)` `=(1+Delta){(1-grad)f(x)}` `=(1+Delta)[f(x)-{f(x)-f(x-h))]` `=(1+Delta)f(x-h)=Ef(x-h)` `[because (E=1+Delta)]` `=f(x)=1*f(x)` Thus, `(1+Delta ) (1-grad)f(x)=1*f(x),` for any function `f (x). `therefore (1+Delta)(1+grad)=1` |
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