InterviewSolution
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The value of `(.^(21)C_(1) - .^(10)C_(1)) + (.^(21)C_(2) - .^(10)C_(2)) + (.^(21)C_(3) - .^(10)C_(3)) + (.^(21)C_(4) - .^(10)C_(4)) + … + (.^(21)C_(10) - .^(10)C_(10))` isA. `2^(20) - 2^(10)`B. `2^(21) - 2^(11)`C. `2^(21) - 2^(10)`D. `2^(20) - 2^(9)` |
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Answer» Correct Answer - A We have `(.^(21)C_(1)+.^(21)C_(2)"....."+.^(21)C_(10))-(.^(10)C_(1)+.^(10)C_(2)"....".^(10)C_(10))` `= 1/2[.^(21)C_(0)+.^(21)C_(1)+.^(21)C_(2)+"..."+.^(21)C_(21)]-2^(10)` `= 2^(20) - 2^(10)` |
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