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The value of `50 sum_(r=1)^(49)(2r^(2) - 48r +1)/((50-r).""^(50)C_(r))` is `"_____"`. |
Answer» Correct Answer - 2499 `underset(r=1)overset(49)sum(2r^(2)-48r+1)/((50-r)..^(50)C_(r))= underset(r=1)overset(49)sum((r+1)^2-r(50-r))/((50-r).^(50)C_(r))` `= underset(r=1)overset(49)sum(((r+1^(2)))/((50-r)..^(50)C_(r))-(r)/(.^(50)C_(r)))` `=underset(r=1)overset(49)sum((r+1)/((50-r)((.^(50)C_(r))/(r+1)))-(r)/(.^(50)C_(r)))` `=underset(r=1)overset(49)sum((r+1)/(.^(50)C_(r+1))-(r)/(.^(50)C_(r)))` `=(50)/(.^(50)C_(50))-(r)/(.^(50)C_(1))` `= 50 - 1/50` |
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