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The value of `[a-b b-c c-a]` is equal to |
Answer» Correct Answer - A `[(a-b,b-c,c-a)]` `={(a-b)xx(b-c)}.(c-a)` `=(axxb-axxc-bxxb+bxxc).(c-a)` `=(axxb+cxxa+bxxc).(c-a)` `=(axxb).c-(bxxc).a` `=[abc]-[abc]=0` |
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